Converting Numbers into their Words Equivalent in C++
#include <iostream>
#include <string.h>
#include <string>
using namespace std;
/*
The program converts a number to its word equivalent.
For example, 1 One ,2 -> two ,3 -> three .............
*/
unsigned long long int Denominations[] = {1000000000000000000,1000000000000000,
1000000000000,1000000000,1000000
,1000,100,1};
const int No_Of_Denums = sizeof(Denominations)/sizeof(long long int);
char Ones[][20] = {"zero","one ","two ","three ","four ","five ","six ",
"seven ","eight ","nine "};
char Tens[][20] = {"twenty ","thirty ","forty ","fifty ","sixty ",
"seventy ","eighty ","ninety "};
char Scale[][20] = {"hexillion ","quintillion ","quadrillion ","trillion ","billion ","million ",
"thousand ","hundred ",""};
char Teens[][20] = {"ten ","eleven ","twelve ","thirteen ",
"fourteen ","fifteen ","sixteen ","seventeen ","eighteen "
,"nineteen "};
string UnderHundred(int n)
{
// n is known to be under 1000. Hence first split up it into 3 numbers
int n1,n2,n3;
n1=n%10; n/=10;
n2=n%10; n/=10;
n3=n%10;
string s="";
if (n3!=0)
{
s+=Ones[n3];
s+="hundred ";
}
if (n2!=0)
{
if (n2==1) //Different construction for Teens, ten inclusive
{
s+=Teens[n1];
return s;
}
s+=Tens[n2-2];
s.replace(s.length()-1,1,"-");
}
s+=Ones[n1];
return s;
}
string Words(unsigned long long int n)
{
int DenumCount[No_Of_Denums] = {0};
int DenumPointer=0;
while (true)
{
if (n < Denominations[DenumPointer])
{
DenumPointer++;
if (DenumPointer>=No_Of_Denums)
{
break;
}
continue;
}
DenumCount[DenumPointer]++;
n-=Denominations[DenumPointer];
}
string s="";
//Now create a string on the basis of those values
for (int i=0;i<No_Of_Denums;i++)
{
if (DenumCount[i]==0) continue;
s+=UnderHundred(DenumCount[i]);
s+=Scale[i];
}
//Convert to first letter to ucase
s[0] = toupper(s[0]);
return s;
}
int main()
{
unsigned long long int i;
unsigned long long int Limit = 0xFFFFFFFFFFFFFFFF;
cout << "Print the number you wish to convert. (0) to exit\n";
cout << Limit <<" is the limit.\n\n";
while(true)
{
cout << "Enter a number to find the word spell\n" << endl;
cin >> i;
if (!i) break;
string s = Words(i);
cout << Words(i) << endl;
}
system("pause");
return 0;
}
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